Six-year NFL veteran defensive tackle Johnathan Hankins signed a two-year extension with the Oakland Raiders, according to ESPN’s Adam Schefter. As of this posting, the exact financial details are still not available to the public. Hankins spent the 2018 season with the Oakland Raiders but has also played for the New York Giants and the Indianapolis Colts.
Johnathan Hankins, Oakland Raiders Agree to Two-Year Deal
Hankins appeared in 15 games for the Silver and Black, starting 14 as a first-year member of the Raiders. During his time on the field, the defensive tackle recorded 36 tackles, two quarterback hits, and two fumble recoveries. Pro Football Focus graded Hankins as the 76th-best defensive tackle in the league.
Hankins initially joined the NFL as a second-round pick in the 2013 NFL Draft. Selected by the New York Giants, Hankins appeared in 11 games as a rookie, but didn’t record a single start. Throughout his first year in the league, Hankins recorded 16 tackles, two tackles for loss, and two quarterback hits.
After not starting a game as a rookie, Hankins started all 16 games during his second year in the league. Hankins broke out in a big way, recording seven sacks, 51 tackles, and 12 quarterback hits over the course of the season. In 2015, Hankins started nine games before an injury prematurely ended his season. During his truncated year, Hankins didn’t record a single sack but still managed to record 30 tackles, two quarterback hits, and one forced fumble.
Hankins started all 16 games during the final year of his rookie contact. The former second-round pick recorded two sacks, 44 tackles, and six quarterback hits for the 11-5 New York Giants. Following the season, Hankins joined the Indianapolis Colts on a three-year, $30 million deal. However, Hankins spent just one year in Indianapolis, recording two sacks, 44 tackles, and six quarterback hits. Hankins then signed a one-year deal with Oakland prior to the 2018 season.
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